将选择的图片显示在listview中,并显示filename,path和type的简单实例

  

复制代码 代码如下:

  if (openFileDialog1.ShowDialog() == DialogResult.OK)

  {

  listView1.Items.Clear();

  string[] files = openFileDialog1.FileNames; //定义一个数组,获取选择的文件

  string[] fileinfo = new string[3];  //定义一个数组,用于存储文件信息

  for (int i = 0; i < files.Length; i++)  //遍历文件数组

  {

  string path = files[i].ToString();  //获取文件路径

  //截取文件名字

  string fileName = path.Substring(path.LastIndexOf("\\") + 1, path.Length - 1 - path.LastIndexOf("\\"));

  //截取文件类型

  string fileType = fileName.Substring(fileName.LastIndexOf(".") + 1, fileName.Length - 1 - fileName.LastIndexOf("."));

  fileinfo[0] = fileName;

  fileinfo[1] = path;

  fileinfo[2] = fileType;

  ListViewItem lvi = new ListViewItem(fileinfo);

  listView1.Items.Add(lvi);

  }

  }

  注释:ListView1, View 属性为Details

  OpenFileDialog1,Multiselect属性为true